Divide an array into two arrays, one containing odd integers and another containing even integers

Posted on Apr 23, 2020

C program to divide an array into two arrays, one containing odd integers and another containing even integers.

Program 

#include<stdio.h>
#include<conio.h>
#define MAX 50

void read_array(int a[MAX], int n)
{
    int i;
    for(i=0;i<n;i++)
    {
        printf("Element %d\t:",i+1);
        scanf("%d",&a[i]);
    }
}

void print_array(int a[MAX], int n)
{
    int i;
    for(i=0;i<n;i++)
    {
        printf("Element %d\t:%d\n",i+1,a[i]);
    }
}

void main()
{
    int arr[MAX], odd[MAX], even[MAX];
    int n, i, n_odd, n_even;

    printf("Enter the number of elements in the array\t:");
    scanf("%d",&n);

    printf("Enter the elements of the array\n");
    read_array(arr, n);

    n_odd = 0;
    n_even = 0;
    for(i=0;i<n;i++)
    {
        if(arr[i]%2==0)
        {
            even[n_even] = arr[i];
            n_even++;
        }
        else
        {
            odd[n_odd] = arr[i];
            n_odd++;
        }
    }

    printf("\nEven integers array\n");
    print_array(even, n_even);
    printf("\nOdd integers array\n");
    print_array(odd, n_odd);

    getch();
}
C++

Output 

Enter the number of elements in the array       :8
Enter the elements of the array
Element 1       :12
Element 2       :25
Element 3       :56
Element 4       :69
Element 5       :98
Element 6       :85
Element 7       :54
Element 8       :41

Even integers array
Element 1       :12
Element 2       :56
Element 3       :98
Element 4       :54

Odd integers array
Element 1       :25
Element 2       :69
Element 3       :85
Element 4       :41
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