Delete all the occurrences of a particular number from the array

Posted on Apr 24, 2020

C program to delete all the occurrences of a particular number from the array.

Program

#include<stdio.h>
#include<conio.h>
#define MAX 50

void read_array(int a[MAX], int n)
{
    int i;
    for(i=0;i<n;i++)
    {
        printf("Element %d\t:",i+1);
        scanf("%d",&a[i]);
    }
}

void print_array(int a[MAX], int n)
{
    int i;
    for(i=0;i<n;i++)
    {
        printf("Element %d\t:%d\n",i+1,a[i]);
    }
}

void delete(int a[MAX], int n, int num)
{
    int i, j, flag;

    flag = 0;
    for(i=0;i<n;i++)
    {
        if(a[i] == num)
        {
            for(j=i;j<=n-1;j++)
            {
                a[j] = a[j+1];
            }
            n = n-1;
            flag = 1;
        }
    }

    if(flag == 1)
    {
        printf("\nModified array is\n");
        print_array(a, n);
    }
    else
    {
        printf("\nElement to be deleted not found");
    }
}

void main()
{
    int arr[MAX];
    int i, n, num;

    printf("Enter the number of elements in the array\t:");
    scanf("%d",&n);

    printf("Enter the elements of the array\n");
    read_array(arr, n);

    printf("Enter the element to be deleted\t:");
    scanf("%d",&num);

    delete(arr, n, num);

    getch();
}

Output

Enter the number of elements in the array       :8
Enter the elements of the array
Element 1       :12
Element 2       :23
Element 3       :25
Element 4       :12
Element 5       :23
Element 6       :12
Element 7       :15
Element 8       :12
Enter the element to be deleted :12

Modified array is
Element 1       :23
Element 2       :25
Element 3       :23
Element 4       :15