Count even and odd numbers in an array

Posted on Apr 23, 2020

C program to count even and odd numbers in an array.

Program

#include<stdio.h>
#include<conio.h>
#define MAX 50

void main()
{
	int arr[MAX];
    int i, n;
    int count_even, count_odd;

    printf("Enter the number of elements in the array\t:");
    scanf("%d",&n);
    printf("Enter the elements\n");
    for(i=0;i<n;i++)
    {
        printf("Element %d\t:",i+1);
        scanf("%d",&arr[i]);
    }

    count_even = 0;
    count_odd = 0;
    for(i=0;i<n;i++)
    {
        if(arr[i]%2==0)
        {
            count_even++;
        }
        else
        {
            count_odd++;
        }
    }
    printf("\nTotal count of even numbers\t:%d",count_even);
    printf("\nTotal count of odd numbers\t:%d",count_odd);

    getch();
}

Output

Enter the number of elements in the array       :8
Enter the elements
Element 1       :1
Element 2       :2
Element 3       :3
Element 4       :43
Element 5       :54
Element 6       :6
Element 7       :7
Element 8       :87

Total count of even numbers     :3
Total count of odd numbers      :5